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Chemistry 7 Online
OpenStudy (anonymous):

If 13.8 moles of carbon (C), with a density of 2.26 g/mL, are needed for a chemical reaction, how many milliliters of carbon are needed?

OpenStudy (anonymous):

I just need help understanding how to get to mL. What equation do I set up to solve this?

OpenStudy (anonymous):

mass C = 13.8 x 12.011 g/mol=165.75g V = 165.75 g/ 2.26 g/mL= 73.3 mL

OpenStudy (anonymous):

I still don't understand exactly what you did. Could you explain please?

OpenStudy (anonymous):

I just took what I saw on Yahoo answers.

OpenStudy (anonymous):

I just don't get where the 12.011 came from....

OpenStudy (anonymous):

Unless it's supposed to be the mass of Carbon but I have that as 12.010 so maybe that's where I was thrown off. Thanks though.

OpenStudy (anonymous):

I only assume. I myself am not too smart in Chemistry, but I try to help in any way possible. If I knew exactly what to search I'd be willing to help further, but from what calculations you pulled and from what I saw on Yahoo answers my best guess would be that 12.011 is the mass of Carbon.

OpenStudy (anonymous):

This number, 12.01, is the mass in grams of one mole of carbon. So maybe it is 12.010.

OpenStudy (anonymous):

Alright thank you. I've read your questions btw, if I knew how to do them I'd help! Sorry.

OpenStudy (anonymous):

But Google says 12.0107, so rounding up could be a solution as which to why the other person got 12.011. Hopefully you get an accurate answer.

OpenStudy (anonymous):

It was a multiple choice question and 73.3 was a choice so I'm assuming that's correct.

OpenStudy (anonymous):

Ah, hopefully. Let me know how it goes.

OpenStudy (anonymous):

That was the right answer.

OpenStudy (anonymous):

YAY

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