Question

The number of 3 digit even numbers that canbe formed using the 5 digits 4,6,7,8,9 no digit being repeated in a number is?

Answer 1

@asnaseer help plzz

Answer 2

@Zarkon plz help

Answer 3

Think about how you can put only 4,6,8 in the last digit.

Answer 4

no the answer is 36

Answer 5

Lol that wasn't even the answer.

Answer 6

I guess that permutations come handy here.

Answer 7

3*4*3 ...

Answer 8

how??@FoolForMath

Answer 9

For the last digit there are three choices, for the second there are 4 and for the first there are 3 ...

Answer 10

ok i get it..

Answer 11

Glad to help :)

Answer 12

plzz look at my next question..

Answer 13

yeah @ParthKohli is heading in the right direction.

you have three digits.
the last one can only be filled by 4,6, or 8 since the digit has to be even. so 3 ways
Now, after this 4 options are left and you can fill the middle digit by any of the 4 options. no constraints here. so 4 ways. and next, 3 options are left, so 3 ways.

so total no. of ways = 3x4x3 = 36.