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Mathematics 19 Online
OpenStudy (anonymous):

Need help with complex numbers

Parth (parthkohli):

\(\Large \color{MidnightBlue}{\Rightarrow i = \sqrt{1} }\) The only complex number I know of lol :P

OpenStudy (amorfide):

square root of -1

Parth (parthkohli):

-1 yes, I meant that

OpenStudy (apoorvk):

umm umm.. \[i=\sqrt{−1}\]

Parth (parthkohli):

@c0rtez Go ahead

OpenStudy (anonymous):

????

Parth (parthkohli):

Cortez, what do you need help with?

OpenStudy (anonymous):

hold on Im trying to write the question

OpenStudy (apoorvk):

so, for example, \[\sqrt{-4} = +2\sqrt{-1}, -2\sqrt{-1} = +2i, -2i\]

OpenStudy (anonymous):

\[z_{1} = \sqrt{3}+i\] \[z_{2} = 1/2(\cos 2pi/3 + i \sin 2pi/3)\] find: \[z_{1}/z_{2}\]\[z_{1}^{6} * z_{2}^{}3\] in both algebraic and polar forms.

OpenStudy (anonymous):

I solved z1/z2 but the algebraic answer is not the same as polar.

OpenStudy (amorfide):

sorry no idea what polar form is

OpenStudy (apoorvk):

do you know Euler's form? Use that

OpenStudy (anonymous):

I wrote z1 in polar form: z1= 2(Cos pi/6 + iSin pi/6) z1/z2 = 4(Cos-pi/2 + iSin -pi/2) [polar form] z1/z2 = 0 [algebraic form]

OpenStudy (apoorvk):

okay do you know this?|dw:1337446685167:dw|

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