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OpenStudy (anonymous):
Need help with complex numbers
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Parth (parthkohli):
\(\Large \color{MidnightBlue}{\Rightarrow i = \sqrt{1} }\)
The only complex number I know of lol :P
OpenStudy (amorfide):
square root of -1
Parth (parthkohli):
-1 yes, I meant that
OpenStudy (apoorvk):
umm umm..
\[i=\sqrt{−1}\]
Parth (parthkohli):
@c0rtez Go ahead
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OpenStudy (anonymous):
????
Parth (parthkohli):
Cortez, what do you need help with?
OpenStudy (anonymous):
hold on Im trying to write the question
OpenStudy (apoorvk):
so, for example,
\[\sqrt{-4} = +2\sqrt{-1}, -2\sqrt{-1} = +2i, -2i\]
OpenStudy (anonymous):
\[z_{1} = \sqrt{3}+i\] \[z_{2} = 1/2(\cos 2pi/3 + i \sin 2pi/3)\]
find:
\[z_{1}/z_{2}\]\[z_{1}^{6} * z_{2}^{}3\]
in both algebraic and polar forms.
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OpenStudy (anonymous):
I solved z1/z2 but the algebraic answer is not the same as polar.
OpenStudy (amorfide):
sorry no idea what polar form is
OpenStudy (apoorvk):
do you know Euler's form? Use that
OpenStudy (anonymous):
I wrote z1 in polar form: z1= 2(Cos pi/6 + iSin pi/6)
z1/z2 = 4(Cos-pi/2 + iSin -pi/2) [polar form]
z1/z2 = 0 [algebraic form]
OpenStudy (apoorvk):
okay do you know this?|dw:1337446685167:dw|
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