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The equation shows one mole of ethanol fuel being burned in oxygen. Convert the energy released into its equivalent mass. C2H5OH(l) + 3 O2(g) Æ 2 CO2(g) + 3 H2O (l) ΔH = -1418 kJ/mol
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E=mc^2
i still dont undererstand it though...can you do it step by step?
E=energy m=mass c=speed of light
For burning one mole of ethanol, energy released = 1418 kJ By Einstein's mass - energy relationship E=mc^2 1418x10^3 = m (3x10^8)^2 m= (1418x10^3) / (3x10^8)^2=? I hope I'm not incorrect... I haven't done anything like that for a month :(
E= ΔH = -1418 kJ/mol
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