Question

evaluate using the substitution method: 8/(x-9)^3 dy

a. 2/(x-9)^4+C
b. -4/(x-9)^2+C
c. -2/(x-9)^2+C
d. 4/(x-9)^2+C

Answer 1

Pretty straight forward, using the formula:
u = x - 9 --> du = ..
Plug it in:

Answer 2

I got A at first but I didn't know if it was correct or not...

Answer 3

Sorry, try again!

Answer 4

Can you show your steps here?

Answer 5

u=x-9 du=dx
\[\int\limits 8/(x-9)^3dx=8\int\limits1/u^3 du=-4/u^2+c=-4/(x-9)^2+c\]