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evaluate using the substitution method: 8/(x-9)^3 dy a. 2/(x-9)^4+C b. -4/(x-9)^2+C c. -2/(x-9)^2+C d. 4/(x-9)^2+C
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Pretty straight forward, using the formula: u = x - 9 --> du = .. Plug it in:
I got A at first but I didn't know if it was correct or not...
Sorry, try again!
Can you show your steps here?
u=x-9 du=dx \[\int\limits 8/(x-9)^3dx=8\int\limits1/u^3 du=-4/u^2+c=-4/(x-9)^2+c\]
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