Question

HELP , picture added !!!

Answer 1

1st the index law of zero

\[a^0 = 1\]

any base to a power of zero is 1

so in your question

\[(2x)^0 = 1\]

this leaves

\[4^2\times4^x = 4^2\]

divide both sides by

\[4^2\]

and hopefully the solution is obvious

Answer 2

what i dont get it

Answer 3

?

Answer 4

your question is

\[(2x)^0 \times4^2 \times4^x = 4^2\]

the 1st step is to divide both sides by 4^2

this gives

\[(2x)^0 \times4^x = 1\]

do you know about the power of zero...?