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Find the area of an equilateral triangle (regular 3-gon) with the given measurement. 6-inch radius A = sq. in.
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what radius, circum or in?
For equilateral triangles, when s = the length of a side, the area equals s squared times the square root of 3 over 4 (area = s^2(sqrt(3)/4)). So when s = 6, the area = 36*sqrt(3)/4 = 9*sqrt(3). Hope this helps better your understanding.
But here s is not 6.
Radius of a triangle?? How?
ah, true. but i only did an example...
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