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Chemistry 11 Online
OpenStudy (anonymous):

*Please Help! For a process, if the enthalpy change of a system is 1.25 ' 10^5 J and the entropy change is 300.0 J/K... Can someone help me calculate the free energy change of the system at 290 K?

OpenStudy (anonymous):

\[\Delta G= \Delta H -T \Delta S\]

OpenStudy (anonymous):

Come on there's a reason that I didn't reference Y! Answers :-)

OpenStudy (anonymous):

Please answer!

OpenStudy (anonymous):

@dagnew can you answer?

OpenStudy (anonymous):

I know the formula, I just need some assistance with the steps :-)

OpenStudy (anonymous):

ΔH = 1.25 ' 10^5 J . TΔS = 290 K * 300.0 J/K. so

OpenStudy (anonymous):

THANKS!

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