Question

*Please Help!
For a process, if the enthalpy change of a system is 1.25 ' 10^5 J and the entropy change is 300.0 J/K... Can someone help me calculate the free energy change of the system at 290 K?

Answer 1

\[\Delta G= \Delta H -T \Delta S\]

Answer 2

Come on there's a reason that I didn't reference Y! Answers :-)

Answer 3

Please answer!

Answer 4

@dagnew can you answer?

Answer 5

I know the formula, I just need some assistance with the steps :-)

Answer 6

ΔH = 1.25 ' 10^5 J . TΔS = 290 K * 300.0 J/K. so

Answer 7

THANKS!