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Mathematics 22 Online
OpenStudy (gabylovesyou):

What happens to the mean, median and mode for the data shown if the outlier is eliminated? 14 , 15 , 22 , 15 , 44 , 16 , 17 , 13

OpenStudy (slaaibak):

step 1: calculate the mean. calculate the mode. calculate the median. step 2: delete the outlier step 3: repeat step 1 step 4: ??? Step 5: PROFIT!

OpenStudy (gabylovesyou):

What is the outlier?

OpenStudy (slaaibak):

Which one do you think?

OpenStudy (gabylovesyou):

idk 22 or 44?

OpenStudy (slaaibak):

44. "In statistics, an outlier is an observation that is numerically distant from the rest of the data."

OpenStudy (gabylovesyou):

ohhh ok :D

OpenStudy (gabylovesyou):

With outlier Mean : 19.5 Median: 15.5 Mode: 15

OpenStudy (gabylovesyou):

am i right?

OpenStudy (anonymous):

The median is not really affected by the outlier, but the mean is, and mode can potentially be, if the outlier itself is the largest value.,

OpenStudy (anonymous):

For instance, let us suppose that the outlier was a really large value. Including the outlier in our calculations to get the mean, we find that the mean is very large

OpenStudy (anonymous):

To really find out what happens, what you should do is first calculate the mean, median and mode WITH the outlier, and then calculate those 3 statistical values again WITHOUT the outlier. Observe for differences.

OpenStudy (gabylovesyou):

i calculated with the outlier am i right? Mean : 19.5 Median: 15.5 Mode: 15

OpenStudy (slaaibak):

QRA, the mode won't be affected. The median would be affected. Also the mean.

OpenStudy (anonymous):

First of all, have you identified which value is the outlier?

OpenStudy (gabylovesyou):

yes 44

OpenStudy (anonymous):

Actually @slaaibak, is not the mode that highest value (though that is one definition), or one of the peaks on the visual display? If it is the highest value, then the mode will be affected

OpenStudy (anonymous):

The mode is affected in that if the outlier is included, then the mode is the outlier.

OpenStudy (slaaibak):

The mode is the value that occurs the most.

OpenStudy (anonymous):

Let me check my statistics textbook. :D

OpenStudy (gabylovesyou):

am i right??? Mean : 19.5 Median: 15.5 Mode: 15

OpenStudy (gabylovesyou):

That is with the outlier

OpenStudy (anonymous):

A mode: a hump or local high point in the shape of the distribution of a variable.

jimthompson5910 (jim_thompson5910):

yes Gabylovesyou you are correct, those the correct values if you include the outlier

OpenStudy (gabylovesyou):

thank you @jim_thompson5910

OpenStudy (anonymous):

We could assume that this set of numbers is for a quantitative variable, and draw out a histogram and see that 44 in fact, is the mode.

jimthompson5910 (jim_thompson5910):

yw

OpenStudy (anonymous):

Sorry I went on a tangent there.

jimthompson5910 (jim_thompson5910):

The other posters have gone over the basics and the answers. I'm just posting this to tidy everything up With Outlier mean = 19.5 median = 15.5 mode = 15 Without Outlier mean = 16 median = 15 mode = 15 So the mean and median are affected/changed when the outlier is eliminated.

OpenStudy (anonymous):

@Gabylovesyou, what is the definition of the mode that you use in class or for this question?

OpenStudy (gabylovesyou):

mode = most! in this example the mode is 15

jimthompson5910 (jim_thompson5910):

the mode is the most frequent value, I'm not sure which definition you're thinking of QRAwarrior

OpenStudy (anonymous):

Oh ok I understand what I did wrong. The mode is the highest peak because it is the value that has been recorded the most.

OpenStudy (anonymous):

Sorry about that.

OpenStudy (slaaibak):

QRA you're taking the mode in a different context here.. you're thinking about probabilities assigned etc. Thats with probability distributions, where the max is the point that is most likely to occur

OpenStudy (anonymous):

for example: 15,15,15,15,15,15,16,24,25 15 would be the highest bar

OpenStudy (anonymous):

@slaaibak I think it was a misunderstanding, see above post

OpenStudy (slaaibak):

Shot, no problem

OpenStudy (gabylovesyou):

its ok @QRAwarrior

OpenStudy (gabylovesyou):

Im going to give u a medal for trying :D

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