Question

for what values of a and b will the vertex of the graph of y=ax2 +bx be located at (-1, -2)?

Answer 1

The vertex is (h,k) = (-1,-2), so h = -1 and k = -2

y = a(x-h)^2 + k

y = a(x-(-1))^2 - 2

y = a(x+1)^2 - 2

y = a(x^2+2x+1) - 2

y = ax^2+2ax+a - 2


Now because the constant term is 0, this means a-2 = 0 ---> a = 2


So because a = 2, we know


y = ax^2+2ax + a-2

y = 2x^2+2*2x+2-2

y = 2x^2+4x


So the graph of y = 2x^2+4x will have a vertex of (-1,-2)

Answer 2

ooooooooooooh problem i miss typed that its
for what values of a and b will the vertex of the graph of y=ax^2 +bx be located at (-1, -2)?

Answer 3

I knew what you meant, so no worries

Answer 4

ooooooooooooooh thank you

Answer 5

you're welcome