Question

which of the following is the solution to the inequality x^2+6x≥7?

Answer 1

folowing?

Answer 2

sorry wait a minute
what is the the solution to the inequality

Answer 3

math book
im new

Answer 4

do u hve the answers,

Answer 5

yeah a few

Answer 6

show them, here...

Answer 7

x≥7 or x≤-1
x≤-7 or x≥1
x≤7 and x≥-1
x≥-7 and x≤1

Answer 8

@satellite73 ...Check if i am write

\[x^{2}+6x \ge7\]
\[x(x+6)\ge 7\]
\[x \ge 7 or x \ge 1\]

Answer 9

sorry no not right

Answer 10

of course my answer was wrong too
should be
\[x^2+6x-7\geq0\]
\[(x+7)(x-1)\geq 0\]
\(x\leq -7\) or \(x\geq 1\)

Answer 11

how can the sign change...?

Answer 12

Sat got wrong? D:
is it Armageddon?

Answer 13

zeros of the quadratic are -7 and 1 and we know that the graph is a parabola that faces up and looks something like this

Answer 14

so it is negative between the zeros i.e. for \(-7<x<1\) and positive outside them, i.e. for \(x\leq-7\) or \(x\geq 1\)

Answer 15

oooooh thank you i get it now