ten students belong to a school club. Five of the members are juniors. If 2 students are chosen at random to serve as club officers, what is the probability that the officers will both be juniors?
Total 10 students 5 members are juniors We have to choose 2 students Do you know combinations @erica123 ?
no i need help on that
no its a multiple choice question A. 1/5 B. 2/9 . 5/18 D. 2/5
b 2/9
i need to know how!
i dont want just the answer
Good erica, I'll explain you
First tell me the probability of choosing 1 junior from these 10 ( you know that there are 5 juniors among the 10)@erica123
choose 2 juniors from 5 = C(5,2) = 10 and n(S) = C(10,2) = 45 so the prob = 10/45 = 2/9
1/2 ? isnt it 5/10 are juniors?
ill tell u how , the chance for choosing the 1st student and hes /shes junior is 5/10 the chance for choosing the 2st student and hes /shes junior is 4/9 5/10 * 4/9 = 2/9 #
Yeah it's 1/2 Now choose 1 more junior from 9 people ( we have 4 juniors now) @erica123
4/9
wait why isnt it from 10 ?
Because we have already chosen 1 junior so we have 9 people now
ohh ok so its 4/9 but what do i do now? do i add subtract/ multiply those fractions
You need to multiply the two probabilities
20/90
So what's the correct option?
B. 2/9 because you can simplify 20/90 ?
Yeah:) you're right Did you understand?
yes :) thanks so much! you're a great help! =)
You're welcome:D
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