Calculate the discriminant of the Function shown and explain in complete sentences which method(s) could be used to solve. using the graph and show work so i get it please
the discriminant of the equation \[ax^2 + bx + x = 0\] is \[\Delta = b^2- 4ac\] the discriminant tells us how many solutions the equation has, if its negative there are none, if its positive there are two, and if its zero there is one repeated solution eg \[5x^2 + 6x - 2 = 0\] so: a= 5 b= 6 c = -2 \[\Delta =b^2-4ac= 6^2 -4(5)(-2) = 36 +40 =76\] which is positive so there are two solutions.
can you tell me the values of a, b, and c for your equation?
hello?
y = -0.57x^2 + 6.79x - 16.68 this is the equation idk if this is what you ment..
ax^2 + bx + c = 0 -0.57x^2 + 6.79x - 16.68 = 0 Could you match them to find your a, b, c = .......... => Δ = b^2−4ac = .....
@firebabe do you follow?
this is the answer i got ... 6.79^2 - 4(-.57) (-16.68) = 46.1041 - 38.0304 = 8.0737
yep
i dont get what it means by explain in complete sentences what methods can be used tho.. what does it mean what methods?
In order to solve for quadratic equation, you should have learned other much simpler method. Do you know which one?
like factoring or completing the square?
Correct, that's how you should elaborate on which method to solve!
its confusing to me with all the decimals D:
That's quite understandable! Practice more and asked the you'll be familiar with Δ in no time :)
Is it possible to solve this problem with factorization method?
uhm..
The answer is Nope --> the only method for this one is applying Δ!
what is the quadratic formula method?
Δ=b^2−4ac You've just learned it, remember!
oh, haha i knew that! sorry!
When you start learn new stuff: Learn WHAT it is + HOW to process :)
I'm glad you've learned this cool quadratic method from this site :)
well you made it easier for me, thanks! this is lame Q. but why cant i use factoring or completing the square
You just factor when you can guess P (product) and S (sum) of the roots, while quadratic method is applied for ALL quadratic equation ( second degree polynomial :)
man you still on this problem? good lord!
tell me about it...
its a long activity!
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