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Mathematics 6 Online
OpenStudy (asylum15):

Solve for x

OpenStudy (asylum15):

\[3=8(1-e ^{-4.7x})\]

OpenStudy (apoorvk):

Take natural log of both sides and proceed.

OpenStudy (asylum15):

Could you comment further?

OpenStudy (lgbasallote):

wouldnt dividing both sides by 8 first be easier?

OpenStudy (mimi_x3):

what about expanding it? Might be easier..

OpenStudy (lgbasallote):

\[\frac{3}{8} = 1 - e^{-4.7x}\] \[\frac{3}{8} - \frac{8}{8} = -e^{-4.7x}\]

OpenStudy (mimi_x3):

\[3= 8-8e^{-4.7x} => -8e^{4.7x} = -5\] then take \(ln\) both sides.

OpenStudy (lgbasallote):

\[-\frac{5}{8} = -e^{-4.7x}\] \[\frac{5}{8} = e^{-4.7x}\] \[\ln \frac{5}{8} = -4.7x \ln e\]

OpenStudy (maheshmeghwal9):

u will get in the end -4.7x= ln (5/8)

OpenStudy (maheshmeghwal9):

now solve for "x".

OpenStudy (lgbasallote):

can you do the last step on your own now @Asylum15

OpenStudy (asylum15):

Yeah, my confusion was over ln. So the ln of \[e ^{-4.7x}\] = -4.7xlne?

OpenStudy (maheshmeghwal9):

ya {ln e=1}

OpenStudy (mimi_x3):

Yes, since \(lne\) is \(1\)

OpenStudy (asylum15):

Ok!, thank you all! If you have any biological questions, I can help! haha

OpenStudy (lgbasallote):

e^(-4.7x) became -4.7x ln e because of "reverse" power rule on logarithms it's supposed to be e^(-4.7x) ln e^(-4.7x) -4.7 x ln e

OpenStudy (asylum15):

Thank you :)

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