Solve for x
\[3=8(1-e ^{-4.7x})\]
Take natural log of both sides and proceed.
Could you comment further?
wouldnt dividing both sides by 8 first be easier?
what about expanding it? Might be easier..
\[\frac{3}{8} = 1 - e^{-4.7x}\] \[\frac{3}{8} - \frac{8}{8} = -e^{-4.7x}\]
\[3= 8-8e^{-4.7x} => -8e^{4.7x} = -5\] then take \(ln\) both sides.
\[-\frac{5}{8} = -e^{-4.7x}\] \[\frac{5}{8} = e^{-4.7x}\] \[\ln \frac{5}{8} = -4.7x \ln e\]
u will get in the end -4.7x= ln (5/8)
now solve for "x".
can you do the last step on your own now @Asylum15
Yeah, my confusion was over ln. So the ln of \[e ^{-4.7x}\] = -4.7xlne?
ya {ln e=1}
Yes, since \(lne\) is \(1\)
Ok!, thank you all! If you have any biological questions, I can help! haha
e^(-4.7x) became -4.7x ln e because of "reverse" power rule on logarithms it's supposed to be e^(-4.7x) ln e^(-4.7x) -4.7 x ln e
Thank you :)
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