Question

We were to asked to get the integral from 0 to infinity of (dx)/(sqrt(x))(x+1). I don't know if I should use the infinite intervals AND the discontinuous integrand or should I just go with one?

Answer 1

split them up first

Answer 2

1 to infity and 0 to 1 should work

Answer 3

So I would split them up first, then use an infinite interval from 1 to infinity and the discontinuous integrand from 0 to 1? :)

Answer 4

yep

Answer 5

Okay. Thanks so much for the help!!

Answer 6

\[\large \int\limits_{0}^{\infty}{dx \over \sqrt {x} \left( x+1 \right)}\]??

Answer 7

substitute \(\large \sqrt x = u\) and \(\large du =\Large \frac 12 \cdot\frac 1 {\sqrt x}\)
\[\Large = 2\int\limits_0^\infty {1 \over u^2+1}du \]

\[\Large = \left[ 2\tan^{-1}(u) \right]_0^\infty=2 \cdot \frac \pi 2-0 = \Huge\pi\]