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Simplify 7 log3 k + 6 log3 m – 9 log3 n
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\[a \log_{3}b= \log_{3}b ^{a} \]
Rewrite each term using that property
What did you get?
I don't get it.
do you mean to write as one log?
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Hint \[7\log_{3} k=\log_{3} k ^{7}\]
another hint: log(MN) = logM + logN
one more hint: log(M/N) = logM - logN
I don't understand what I need to do.
here's an example: log(5) + log(3) = log(5*3) = log(15) i started with the sum of two logs and eventually i ended up with 1 log. that is what you need to do with the expression they gave you.
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