Question

Find dy/dx: y=e^(5-3lnx)

Answer 1

use chain rule

Answer 2

I dont think so he know the chain rule let's help out :)

Answer 3

so this would be 5/(3lnx)?

Answer 4

nope answer would be : -3/x(e^5-3lnx)

Answer 5

could you please show me the steps, i am confused how you get that..

Answer 6

@muhe Don't just give the answer. It is against our CoC. Thanks for understanding.

Answer 7

okay sorry for that I thought he is asking only the answer..

Answer 8

\[y=e^{f(x)} => y'=f'(x) e^{f(x)} \]

Answer 9

This right here will work every time
for something in the form of \[y=e^{f(x)}\]

Answer 10

U differentiate the power of the e first and then multiply it with the function that is how u differentiate the power of the e..

Answer 11

sorry, my battery just died

Answer 12

so, in this case the derivative of 5

Answer 13

\[y'=(5-3 \ln(x))'e^{5-3\ln(x)}\]
using the rule I wrote down

Answer 14

the derivative of 5-3lnx would be -3* 1/x ?

Answer 15

Yes!
So what is y'?

Answer 16

yes exactly

Answer 17

so y' would be -3/x * e^(5-3lnx)

Answer 18

:)
Great job everyone!

Answer 19

thank you =D now I get that !