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You invest $3,000 in an account that has an annual interest rate of 2.5%, compounded continuously. How much money will be in the account after 5 years?
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Last one! @jim_thompson5910
Now we return to the formula A = Pe^(rt) because we're compounding continuously again. In this case, P = 3000, r = 0.025 and t = 5, so this means... A = 3000*e^(0.025*5)
do you remember what to do here?
Could you please remind me what the value of e is?
sure thing
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e is approximately 2.71828
so A = 3000*e^(0.025*5) is approximately A = 3000*2.71828^(0.025*5)
A= 3399
very good
Fantastic! Thank you so so much for all your help again! =)
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anytime, glad I could help you out
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