Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

is anyone good with standard deviations?

OpenStudy (anonymous):

nice! would you be willing to help me?

OpenStudy (anonymous):

what is the best approximation of the standard deviation of the measures -4, -3, 0, 8 and 9?

OpenStudy (amistre64):

is that all your problem states?

OpenStudy (amistre64):

if so, find the mean and subtract it from all the data points, square and add the results then divide by how many data points there are (assuming that this is a population), and take the sqrt of that

OpenStudy (anonymous):

Thanks for the thorough explanation.. I appreciate it!

OpenStudy (amistre64):

your welcome; in formula it reads as:\[\sigma^2=\frac{\sum(x-\mu)^2}{N}\]

OpenStudy (amistre64):

where sigma squared is variance; and standard deviation is the squareroot of variance

OpenStudy (amistre64):

if you need any help working thru that, just ask :)

OpenStudy (anonymous):

yea i might need a little help haha

OpenStudy (amistre64):

ok, find the mean for me, simply add up all the values and divide by how many there are

OpenStudy (anonymous):

2

OpenStudy (amistre64):

subtract 2 from all the points given and list the results then

OpenStudy (anonymous):

-6, -5, -2, 6, 7

OpenStudy (amistre64):

good, now square all those values and add them up

OpenStudy (anonymous):

you get a positive when you square a negative, right?

OpenStudy (amistre64):

yes

OpenStudy (anonymous):

i got 150

OpenStudy (amistre64):

good, thats the top number for our formula; the bottom is just 5 so 150/5 = variance the square root of variance equals our standard deviation; so what do we get?

OpenStudy (anonymous):

30

OpenStudy (anonymous):

the denominator is the amount of numbers that we have?

OpenStudy (amistre64):

depends, if its a population then yes; if its a sample then its one less

OpenStudy (amistre64):

im assuming the data represents a population so divide by the number of data points; 5 in this case

OpenStudy (anonymous):

ok.. so the answer would be 30?

OpenStudy (amistre64):

30 is our variance value; take the square root of that for the standard deviation sqrt(30) = what?

OpenStudy (anonymous):

i got 5.48

OpenStudy (amistre64):

then thats it. Im not sure what you mean by best approx tho; but if you have choices, its bound to be close to that; if not try dividing it by 4 instead of 5

OpenStudy (anonymous):

it was a multiple choice and 5 is the closest to it so I believe that 5 is the answer

OpenStudy (anonymous):

Thank you soooooo much for the fantastic help =]

OpenStudy (amistre64):

youre welcome.

OpenStudy (amistre64):

if we divide by 4 I get 6.12 or so; so it all depends on if they are looking for a population or a sample standard deviation

OpenStudy (anonymous):

I think it's for a population, but it didn't say anything.. I copied down the exact question, but I think you got it right

OpenStudy (amistre64):

good luck ;)

OpenStudy (anonymous):

thanks!

Directrix (directrix):

There's an online standard deviation calculator which might be used later by the Askee once the concept of standard deviation is learned. Attached is a .jpg of the "calculator" results if anyone is interested. http://easycalculation.com/statistics/standard-deviation.php

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!