is anyone good with standard deviations?
nice! would you be willing to help me?
what is the best approximation of the standard deviation of the measures -4, -3, 0, 8 and 9?
is that all your problem states?
if so, find the mean and subtract it from all the data points, square and add the results then divide by how many data points there are (assuming that this is a population), and take the sqrt of that
Thanks for the thorough explanation.. I appreciate it!
your welcome; in formula it reads as:\[\sigma^2=\frac{\sum(x-\mu)^2}{N}\]
where sigma squared is variance; and standard deviation is the squareroot of variance
if you need any help working thru that, just ask :)
yea i might need a little help haha
ok, find the mean for me, simply add up all the values and divide by how many there are
2
subtract 2 from all the points given and list the results then
-6, -5, -2, 6, 7
good, now square all those values and add them up
you get a positive when you square a negative, right?
yes
i got 150
good, thats the top number for our formula; the bottom is just 5 so 150/5 = variance the square root of variance equals our standard deviation; so what do we get?
30
the denominator is the amount of numbers that we have?
depends, if its a population then yes; if its a sample then its one less
im assuming the data represents a population so divide by the number of data points; 5 in this case
ok.. so the answer would be 30?
30 is our variance value; take the square root of that for the standard deviation sqrt(30) = what?
i got 5.48
then thats it. Im not sure what you mean by best approx tho; but if you have choices, its bound to be close to that; if not try dividing it by 4 instead of 5
it was a multiple choice and 5 is the closest to it so I believe that 5 is the answer
Thank you soooooo much for the fantastic help =]
youre welcome.
if we divide by 4 I get 6.12 or so; so it all depends on if they are looking for a population or a sample standard deviation
I think it's for a population, but it didn't say anything.. I copied down the exact question, but I think you got it right
good luck ;)
thanks!
There's an online standard deviation calculator which might be used later by the Askee once the concept of standard deviation is learned. Attached is a .jpg of the "calculator" results if anyone is interested. http://easycalculation.com/statistics/standard-deviation.php
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