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Find the inverse of the given function and use composition to justify the results: h(x)=(x-4)^3
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to "justify your answer" compose \[f\circ f^{-1}(x)\] and arrive at \(f\circ f^{-1}(x)=x\) by algebra
Were did you get the 3 from?
the three came from me not paying sufficient attention it is \[f^{-1}(x)=\sqrt[3]{x}+4\] sorry about that
\[y=(x-4)^4\] \[x=(y-4)^3\] \[\sqrt[3]{x}=y-4\] \[\sqrt[3]{x}+4=y\] \[f^{-1}(x)=\sqrt[3]{x}+4\] looks a lot better
Thanks
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