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find the end behavior f(x)=(x-3)(1-x)(3x-5) Lim f(x) lim f(x) x--> infinity x--> negative infinity
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After expanding \[ f(x)=(1-x) (x-3) (3 x-5)\\ f(x)=-3 x^3+17 x^2-29 x+15\\ \]
A polynomial near Infinity behaves like its term of highest degree, meaning like \[- 3 x^3 \] Hence it approaches -Infinity when x approaches Infinity and it approaches xxx when x approaches -Infinity. Can you find what xxx is?
xxx?
It means find the limit of f(x) when x approaches - Infinity
ok so the answer would be infinity?
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Yes when x approaches - Infinty
ok how did you find that? im really confused
How much is \[ - 4 x^3 \] When x =-10, x=-100, x = - 1000?
ok thanks
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