Question

log(base3)3+log(base3)x=5

Answer 1

@dpaInc

Answer 2

since the logs on the left are of the same base, can you rewrite that left side as one log base 3?

Answer 3

you'll use this property:

log_b (M) + log_b (N) = log_b (M*N)

Answer 4

need help?

Answer 5

Yes, im sorry my brain is a little jumbled

Answer 6

sawright...:)

Answer 7

log_b (M) + log_b (N) = log_b (M*N)
log_3 (3) + log_3 (x) = log_3 ( )

what do you think should go in the parenthesiss

Answer 8

The 5

Answer 9

no... try again... forget about that right side for now... we're just working on the left.

Answer 10

On no its the 3 and x so its 3x =)

Answer 11

yes...

Answer 12

so we have:

log_3 (3x) = 5

correct?

Answer 13

Yes =) So we would divide noth sides by log-3

Answer 14

no....

Answer 15

do you know how to rewrite this logarithm expression in it's exponential form?:

log_3 (3x) = 5

Answer 16

Yes =) the base is -3 and the exponent is 5. So it would be -3^5=3x??

Answer 17

yes... btw, the base is positive 3. the line you see before that is just an underscore to denote the base.

Answer 18

so
3^5 = 3x

Answer 19

you're almost done.. what do you need to do to get x by itself?

Answer 20

Divide by 3 on both sides, and I got 81 =)

Answer 21

yep... ;)

Answer 22

Oh yay! =) Thanks a ton!

Answer 23

your good at these!!!
nice work swimgirly...