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Mathematics 20 Online
OpenStudy (anonymous):

See the equation.

OpenStudy (anonymous):

\[3^{x}(3^{x+2})\]

OpenStudy (anonymous):

=9

OpenStudy (anonymous):

Are you solving for X?

OpenStudy (anonymous):

Yes :)

OpenStudy (anonymous):

Let's see, give me a sec. I think there will be some logarithms in here

OpenStudy (anonymous):

Alright, thanks!

OpenStudy (anonymous):

Ok. so distributing you can see we would get \[3^{2x+2}=9\] We can rewrite 9 as \[3^{2}\]

OpenStudy (anonymous):

So we would get \[3^{2x+2}=3^{2}\] then take the log base 3 of both sides and then \[2x+2=2\]

OpenStudy (anonymous):

Then you can solve for x

OpenStudy (anonymous):

But don't you have to multiply the 3's?

OpenStudy (anonymous):

Oh wait. You multiply its squared to the x?

OpenStudy (anonymous):

You would take the logbase 3 of both sides \[\log_{3} ( 3^{2x+2}) = \log_{3} (3^{2})\]

OpenStudy (anonymous):

leaving you with only exponents You could also maybe see it straight up as well. \[3^{2x+2} = 9 \]

OpenStudy (anonymous):

what is 9 it is 3 squared, so you would know x must be 0

OpenStudy (anonymous):

I don't see how you get rid of the other three without having to make it into a \[3 ^{x^{2}}\]

OpenStudy (anonymous):

Have you ever worked with logarithms? Maybe I am taking the wrong approach ^_^;

OpenStudy (anonymous):

I guess you know this much we can write your equation like \[3^{2x+2}= 3^{2}\]

OpenStudy (anonymous):

No, I'm in geometry hehe. My teacher didn't even tell us that this topic was logarithms!

OpenStudy (anonymous):

Haha. Well in this problem we don't necessarily need them to solve. We see we can write the expression as \[3^{2x+2}= 3^{2}\] each side with the same base so It is clear the exponents on the left must add up to what we have on the right, in our case 2, so x must be 0!

OpenStudy (anonymous):

\[3^{x}(3^{x+2)}=9\]

OpenStudy (anonymous):

Where do you get the 2x?

OpenStudy (anonymous):

Rules of exponents : if we are multiplying like terms we add exponents \[X \times X = X^{2} or X^{1+1}= X^{2}\]

OpenStudy (anonymous):

Okay

OpenStudy (anonymous):

so what I did in your example is \[3^{x+2+x}\]

OpenStudy (anonymous):

combine like terms to get \[3^{2x+2}\]

OpenStudy (anonymous):

I actually meant one, and put two by accident! sorry >_< So it's \[3^{2x+1}=9\]

OpenStudy (anonymous):

so x=4?

OpenStudy (anonymous):

X = 1/2 in this one

OpenStudy (anonymous):

Look at it like this \[3^(2x+1) = 3^{2}\]

OpenStudy (anonymous):

Whoops, should be: \[3^{2x+1} = 3^{2}\]

OpenStudy (anonymous):

We know \[3^{2} = 9\]

OpenStudy (anonymous):

Oh, I see my mistake! I forgot to make the 9 into 3^2

OpenStudy (anonymous):

Thank you ^_^!

OpenStudy (anonymous):

Yeah it is a bit more clear that way :D No problem anytime

OpenStudy (anonymous):

I have more questions about this, and I was hoping if you could answer some of them? I have 9 I don't know out of 30

OpenStudy (anonymous):

Ok sure!

OpenStudy (anonymous):

Thank you so much!

OpenStudy (anonymous):

Not a problem. Hopefully I can be of some help.

OpenStudy (anonymous):

My first fan! :D lol

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