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OpenStudy (anonymous):
4x-2y=-2 3x+y=-4
substitution or elimination to solve
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OpenStudy (anonymous):
You can solve for y in the second equation and then substitute into the first one
to solve for x
OpenStudy (anonymous):
elimination of x or y
OpenStudy (anonymous):
\[y = -4-3x\] then substitute in the first equation for y
OpenStudy (anonymous):
\[4x-2(-4-3x)=-2\]
OpenStudy (anonymous):
.
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OpenStudy (anonymous):
then distribute \[4x+8+6x=-2\]
then combine like terms \[10x+8=-2\]
OpenStudy (anonymous):
solve for x \[10x=-10\]
\[x=-1\]
OpenStudy (anonymous):
Plug that value into one of your equations and you get \[y = -1\]
OpenStudy (anonymous):
mul eq1 by 3 and mul eq2 by 4 then subtract (eq1 -eq2)
OpenStudy (anonymous):
That works also
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OpenStudy (anonymous):
ok Thank you! I'm going to do one on my own to see if I completely understand..
OpenStudy (anonymous):
y=2x-7 x+4y=-1
my answer is (3,-1)
OpenStudy (anonymous):
Not sure those values are correct try plugging them into the second equation
OpenStudy (anonymous):
ok, yes it went in. Thank you
OpenStudy (anonymous):
oh you are right so sorry
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OpenStudy (anonymous):
my mistake very good!
OpenStudy (anonymous):
I just hope I remeber when it comes to finals this week! UGH! night thank you
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