4x-2y=-2 3x+y=-4 substitution or elimination to solve
You can solve for y in the second equation and then substitute into the first one to solve for x
elimination of x or y
\[y = -4-3x\] then substitute in the first equation for y
\[4x-2(-4-3x)=-2\]
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then distribute \[4x+8+6x=-2\] then combine like terms \[10x+8=-2\]
solve for x \[10x=-10\] \[x=-1\]
Plug that value into one of your equations and you get \[y = -1\]
mul eq1 by 3 and mul eq2 by 4 then subtract (eq1 -eq2)
That works also
ok Thank you! I'm going to do one on my own to see if I completely understand..
y=2x-7 x+4y=-1 my answer is (3,-1)
Not sure those values are correct try plugging them into the second equation
ok, yes it went in. Thank you
oh you are right so sorry
my mistake very good!
I just hope I remeber when it comes to finals this week! UGH! night thank you
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