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See equation.
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\[(3/4)^{2x}=64/27\]
Hint: \[\Large \frac{64}{27} = \frac{4^3}{3^3}\]
\[x=-3/2\]
x=1/3?
Oh, how do you get that?
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\[\LARGE \frac{4^3}{3^3} = (\frac{3}{4})^{-3}\]
do you agree with that??
yes
so you now know how x = -2/3 was got?
i mean -3/2
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yes! :)
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