Two substances have different ΔHvaporization values. If given the same number of moles of each substance, and assuming the same amount of heat is applied to both substances, the substance with a higher ΔHvaporization value will convert from a liquid to a gas more quickly. True False
OMG i forgot wat delta H symbolise do u knw??
I think temperature change?
no its not reagarding to temp change wait i m cross checking it ok @Ishaan94
Its enthalpy
i got it :o how to do this qn :P listen here u are saying both are given same heat and here delta H is of vapourisation means it exothermic process mean more delta H in exothermic mean more stability of products ans yes it ll convert into gaes v.quickly. so the ans is true :)
False. delta H of vap is the Heat absorbed per mole.
H is Enthalpy..defined as total heat content of the system
delta H vapourisation is exothermic or endothermic ?? @ASD28803
If the sign is (-) then exo If the sign is (+) then endothermic
i knw i m asking heat of vapoursation is exo or endo process??
hey i chcked and heat of vapourisation i exothermic process so the ans of this qn is true
vaporisation is ---> endothermic.
ok then answer is false :P if the process is endothermic :)
when you put some spirit on your palm, your palm feels cool - because the spirit *absorbs* heat - the molecules utilise that heat to gain kinetic energy and evaporate! So, as the the liquid vaporises, your palm feels cooler. In short, it's endothermic because the molecules of the the liquid need energy to escape the liquid phase - which they get by absorbing heat.
yea i thought it is exo as u knw when we boil water wat happen all the heat is released and heat released mean exo
so i was lil bit confused now confirm its endo thnQ for coming @apoorvk :)
heat is released?? heat is not released exactly - it's not heat. it 'feels' hot because it's at a higher temperature - but eventually, it's the same thing. The molecules of water absorb that heat from the burner, gain KE, and whooshh!!! - convert into steam!
okhay whosssshhh !!! lol bhai ok now i got it :)
No worries ;)
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