Question

Tan x=1.8040. Find x.

Answer 1

Use the inverse tangent to get 61 degrees (I assume you need the angle measure) so tan^-1=60.99935688

Answer 2

sorry I meant to type tan^-1 (1.8040)=60.99935688

Answer 3

well we have sin x = 1.8 cos x
sq. both sides
sin^2 x = 3.24 cos^2 x
1 - cos^2 x = 3.24 cos^2 x
cos^2 x = 1/4.24
=> cos x = 1/2.05, -1/2.05 (approx)
thus x is 2n(pi)+ pi/6 ,, approximately

Answer 4

f(x)=tan(x) is an odd function
f(-x)=-f(x)
-f(-x)=f(x)
So this means
-tan(-x)=tan(x)
So we have two equations
tan(x)=1.804
-tan(-x)=1.804
Let n be an integer
But we also have that tan(x)=tan(x+n*pi)
So we also have -tan(-x)=-tan(-x+n*pi)

So we can rewrite those two equations as

tan(x+n*pi)=1.804
-tan(-x+n*pi)=1.804

Now this means when we have

tan(x+n*pi)=1.804

tan(-x+n*pi)=-1.804

Now arctan( ) of both sides

and blah blah