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In a 30-60-90 triangle, the shorter leg has length of 8√3 m. Find the length of the other leg (L) and the hypotenuse (H).
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The ratios in a 30-60-90 triangle are: \(\Large \color{MidnightBlue}{\Rightarrow x\sqrt3,x,2x }\) So far, we can say that x = 8 x =other leg= 8 2x = hypotenuse = 16
The question says the shorter leg has the length 8√3 m. So x=8√3, the other leg would be x√3 =8√3√3 and the hypotenuse is 2x=2(8√3 m)
Oh oops
Yall have me soo confused
pfenn1 is correct
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Thankyou For helping any how :)
This website explains the special case of a 30-60-90 triangle. http://www.regentsprep.org/Regents/math/algtrig/ATT2/Ltri30.htm This is a handy thing to know.
ok thankyou
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