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Physics 21 Online
OpenStudy (ujjwal):

Question is given below...

OpenStudy (ujjwal):

A physical quantity x is calculated from \[x=(ab ^{2})/\sqrt{c}\]If the % error in measuring a,b,c are 4,2,3 respectively then the % error in measuring x is: a)4% b)6% c)9% d)9.5%

OpenStudy (anonymous):

d

OpenStudy (ujjwal):

I don't want direct answer.. tell me how do you get it?

OpenStudy (anonymous):

c i guess (4*2^2)/sqrt(3)

OpenStudy (anonymous):

if \[x=\frac{a^nb^m}{c^q}\] then the % error in x is \[\frac{\Delta x}{x}\times100=n\times\frac{\Delta a}{a}\times100+m\times\frac{\Delta b}{b}\times100+q\times\frac{\Delta c}{c}\times100\]

OpenStudy (anonymous):

now you can do it.

OpenStudy (ujjwal):

Dhanyabad @ramkrishna ..

OpenStudy (anonymous):

suswagatam. @ujjwal

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