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A physical quantity x is calculated from \[x=(ab ^{2})/\sqrt{c}\]If the % error in measuring a,b,c are 4,2,3 respectively then the % error in measuring x is: a)4% b)6% c)9% d)9.5%
d
I don't want direct answer.. tell me how do you get it?
c i guess (4*2^2)/sqrt(3)
if \[x=\frac{a^nb^m}{c^q}\] then the % error in x is \[\frac{\Delta x}{x}\times100=n\times\frac{\Delta a}{a}\times100+m\times\frac{\Delta b}{b}\times100+q\times\frac{\Delta c}{c}\times100\]
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now you can do it.
Dhanyabad @ramkrishna ..
suswagatam. @ujjwal
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