Question

If [2cosx] + [sinx] = -3, then the range of the function, f(x) = sinx + (sqrt3)cosx in [0, 2pi] is: WHERE [.] denotes the greatest integer function.

Answer 1

@FoolForMath Help? Not getting the required answer here.

Answer 2

@dumbcow Help?

Answer 3

range of f(x) is [-2,2]
set f'(x) = 0 to find min/max

Answer 4

Thats not the given answer.

Answer 5

okay that can only mean:
-1<cosx<-0.5 and sinx<0

Answer 6

-2,2??

Answer 7

Nope. Think more guys. The upper limit needs to be checked according to domain for first condition.

Answer 8

seriously [2cosx] + [sinx] = -3 <--- can it be solved??

Answer 9

Ofcourse it can.
Its too unique man. Check individual ranges.

Answer 10

but cos and sin are never simultaneously 1

Answer 11

[0.542] = 1 ??

Answer 12

No. [0.542] = 0. It refers to the integral part of the number.

Answer 13

is [-0.542] = -1 ??

Answer 14

Yeah.

Answer 15

Makes sense now, right?

Answer 16

yes .. the range is -1,-2