If [2cosx] + [sinx] = -3, then the range of the function, f(x) = sinx + (sqrt3)cosx in [0, 2pi] is: WHERE [.] denotes the greatest integer function.

Question

anonymous · Answer

@FoolForMath Help? Not getting the required answer here.

anonymous · Answer

@dumbcow  Help?

dumbcow · Answer

range of f(x) is [-2,2]
set f'(x) = 0 to find min/max

anonymous · Answer

Thats not the given answer.

apoorvk · Answer

okay that can only mean:
 -1<cosx<-0.5 and sinx<0

experimentx · Answer

-2,2??

anonymous · Answer

Nope. Think more guys. The upper limit needs to be checked according to domain for first condition.

experimentx · Answer

seriously [2cosx] + [sinx] = -3 <--- can it be solved??

anonymous · Answer

Ofcourse it can. 
Its too unique man. Check individual ranges.

experimentx · Answer

but cos and sin are never simultaneously 1

experimentx · Answer

[0.542] = 1 ??

anonymous · Answer

No. [0.542] = 0. It refers to the integral part of the number.

experimentx · Answer

is [-0.542] = -1 ??

anonymous · Answer

Yeah.

anonymous · Answer

Makes sense now, right?

experimentx · Answer

yes .. the range is -1,-2