Question

doing trigs..

prove that \frac {<\[\sin A\]>}{<\[1 + \cos A\]>} + \frac {<\[1 + \cos A\]>}{<\[\sin A\]>} = \[2\csc A\]

oh my god I hope that turns out right. derp.

Answer 1

......... IT DID NOOOOOOOT

Answer 2

lol

Answer 3

\[\frac{\sin A}{1+\cos A}+\frac{1+\cos A}{\sin A} =2\csc A\]

Answer 4

is that it?

Answer 5

anyway if you combine the fractions on left side and use trig identity
sin^2 + cos^2 = 1

then it should work out nicely