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Solve logx + 5 36 = 2 Choose one answer. a. x = 1 b. x = 11 c. x = 13 d. x = 23
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\[\log_{x+5} (36)=2\]
\[\log_{x+5}(36)=\ln (6^{2})\div \ln (x+5)\]
so the équation become \[\ln (6)=\ln (x+5)\]
ok what do i do next
I think its x=1 but I am not positive it that right
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So you can easily conclude that x+5 = 6 x = 1 So the answer is (a)
kk thanks so much for all your help!
to be sure you can replace x by 1.
\[\log_{6} (36)=\ln(6^{2})\div \ln (6)=2\ln (6)\div \ln (6)=2\]
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