Question

suppose i have a conducting cube of side length 1 metre, and a charge q is placed inside it. how can i find the electric field at a point which is at the centre of any face of the cube? (the charge eventually gets dispersed to the surface of the cube, as it is a conductor)

Answer 1

its not a holow tube.

Answer 2

i know, what's your point?

Answer 3

electric field=qd where d is the distance and q is the charge..:) distance can be taken as lenght of the conducter and charge q is the charge of electron or proton.

Answer 4

yes, but the charge will get distributed unevenly on the surface of the cube, that's why i'm having a problem finding the field.

Answer 5

when charge is gets unevenly distributed each charge creats its own electrical field that field is actually equivalent to electric field of a conducter... as electric field is a scalar quantity..:)

Answer 6

Electric field is a vector quantity, and it is not equal to qd it is E = U/d where U is potential difference and d is the distance between two points having these potentials.

Answer 7

actualy E= du/ds. or can be expressed in terms of flux too

Answer 8

Right, your definition is more general one.

Answer 9

Use Gauss Law

Answer 10

its not possible to use gauss law

Answer 11

Is it restricted ?

Answer 12

no, you cannot find the answer using gauss law, at least i think so..

Answer 13

Sorry, I agree.

Answer 14

sorry, it's E=(-dV)/ds

Answer 15

E= \[\sigma/\epsilon\]

Answer 16

In this case Each surface will act like charged conducting surface . The electric field near a charged surface is independent of distance . You can use the same formula to calculate E at the center . The formula is good if l/r <<<<<<

Answer 17

l = side of the cube

Answer 18

when you say that the field is independent of distance, do you mean the distance from the centre of the cube?

Answer 19

yes

Answer 20

in that case,