Question

Using the laws of indicies, simplify, giving your answers with positive indices:

Answer 1

\[18^{x} \times 9^{2+x}\over3^{3x-1} \times 6^{x+1}\]

Answer 2

Hi cwr :)

Answer 3

hi

Answer 4

Tricky problem?

Answer 5

yea tis a bit

Answer 6

we can write 9^2+x as 3 ^(4+2x)

Answer 7

that gives us
3^(4+ 2x - (3x-1) = 3^(5-x)

Answer 8

= 18^x * 3^(5-x)
------------
6^(x+1)

Answer 9

Thats it I guess? :)

Answer 10

well - its a bit more simple - lol