Solve for x: \[\log_2(x^3)-3=2\log_2 x\] I tried solving this by converting everything to base 2: \[\log_2(x^3)-\log_2(8)=2\log_2 x\] Then using the log rules to combine the LHS: \[\log(\frac{x^3}{8})=2\log_2 x\] But I'm stuck on what to do next.
\[\large \log_2(x^3)-3=2\log_2 x\] is it this?
Yep.
get the logs on one side of the equal sign and put that three by itself on the other... what do you have?
oops.. you actually showed your work but my computer is not showing it properly.. can you show me where you got stuck?
One second, I didn't actually put 3 on the other side by itself and instead turned it into a log. Give me a second to see what I get.
Hey thanks! I got it! By putting the x's on one side alone, I was able to simplify the x^3 and x^2 to x and then it was very simple to solve by then. Thanks!
yw.. :)
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