Question

HOW DO I DO THESE TYPE OF PROBLEMS, CAN SOMEONE BREAK IT DOWN? PLEASE

You need 540 mL of a 55% alcohol solution. On hand, you have a 60% alcohol mixture. How much of the 60% alcohol mixture and pure water will you need to obtain the desired solution?

Answer 1

i think you would use 297 ML of alchol and the rest water just my guess

Answer 2

do you know how to set it up as an equation

Answer 3

well i did 540 * .55 and that gave me 297

Answer 4

the 297 is the amount of alcohol you want at the end, but you are not adding pure alcohol, you are adding 60% alcohol.

put the amount of 60% alcohol you add as \(x\) so that will give \(.6x\) amount of alcohol
set this equal to 297 and solve for \(x,\) i.e. solve
\[.6x=297\]

Answer 5

hehehehhe i was right

Answer 6

well sort of

Answer 7

are we gonna argue
cuz I am READY

Answer 8

the question asks how much 60% alcohol you need, and how much pure water you need.

Answer 9

sorry

Answer 10

we set
\[.6x=297\] get
\[x=297\div .6=495\] so you need 469 gallons of 60% alcohol and the rest \(540-495=45\) gallons of water

Answer 11

i meant to write "you need 495 gallons of 60% alcohol and 45 gallons of water

Answer 12

Thank you guys :)

Answer 13

yw

Answer 14

okay i have another one that i need help with :(

Answer 15

Do i Do it the same way?
You need a 30% alcohol solution. On hand, you have a 200 mL of a 15% alcohol mixture. You also have 80% alcohol mixture. How much of the 80% mixture will you need to add to obtain the desired solution?

You will need
____mL of the 80% solution
to obtain
____mL of the desired 30% solution.