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x-9÷√x+3x
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sorry no x on the last 3
\[ \frac{x-9}{\sqrt{x+3}}? \]And what are we supposed to do with it, rationalize it?
What are you supposed to do with it?
the square root is only over the x at the bottom
Okay, \( \dfrac{x-9}{\sqrt{x}+3} \), what are we doing with it?
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on my worksheet it just saids to simplify it
Okay, multiply the top and bottom both by \(\sqrt{x}-3\). This is known as the conjugate of the denominator.
ok so on the top would you get x√(x)-3x-9√(x)+27
I wouldn't actually multiply it through. Expand the denominator and see if you can cancel something out :)
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