please helpp if f(x) is 1-1 and if f(x) is never zero can any be said about h(x) = 1/f(x)? is it also 1-1? Give reasons for your answer?
is that the actual question? Can you state the question given in your class? Seems like it is miswritten or something. What level of math is this? just curious so I know how to answer it, if I can
its first year calculus and that is what is written in the book
I do believe that would also be 1-1. If it were 0, we would run into a problem dividing by 0, but it isn't, and since \(f(x)\) takes unique values for unique \(x\)'s, \(1/f(x)\) must also take unique values.
hmm so just again 1-1 basically means it passes the horizantal and the vertical line test?
1-1 means it passes the horizontal line test. However, it must also pass the vertical line test since that's required to be a function.
could we also prove this by defining a 1-1 function saying let us pick two arbitrary points say a,b and h(a) = 1/f(a) and h(b) = 1/f(b) therefore 1/f(a)=1/f(b) and that implies f(b)=f(a) and that implies b=a and that implies h is a 1-1 function ??
You would prove it by saying that: Suppose h(a)=1/f(a)=h(b)=1/f(b). Then 1/f(a)=1/f(b) so f(a)=f(b). Since f is 1-1, this implies that a=b. Hence, h is also 1-1.
perfect thanks a lot
could you also help me in this other question please i am going to post please
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