Question

Find the indefinite integral:

Integrand of 16x((8x^2)+7)^6

Answer 1

U-sub,
u=8x^2+7
du=16x dx
\[\int\limits u^6 \, du\]
Then integrate

Answer 2

so my answer would be 1/9(8x^2+7)^9?

The last exponent was supposed to be an 8, not a 6 (sorry)

Answer 3

+ C at the end of course

Answer 4

Check your integration, it should be
\[\frac{u^7}{7}+c\]

Answer 5

got it thanks!

Answer 6

welcome :)