Question

. In triangle ABC, AB = 14, AC = 22 and angle A measures 43 degrees. Calculate the area of triangle ABC, correct to the nearest whole unit, and find the length of side BC, correct to the nearest tenth.

Answer 1

i need help with this question plese

Answer 2

area is
\[\frac{1}{2}14\times 22\times \sin(43)\]

Answer 3

thanks but can u plese show work thanks

Answer 4

the work is from the formula that says area of a triangle is one half base times height.

Answer 5

thanks sooo much the drawing makes it soo much esaier to understand

Answer 6

since
\[\sin(43)=\frac{h}{14}\] we know
\[h=14\times \sin(43)\] and so
\[\frac{1}{2}bh =\frac{1}{2}22\times 14\times \sin(43)\]

Answer 7

for the second part of the question you need the law of cosines

Answer 8

do you know it?

Answer 9

yup thanks sooo much!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 10

yw