Question

Solve by substitution, 3x+y=6 and y+2=x

Answer 1

ok

Answer 2

you know that x = (y+2) from the second equation so you subsitute that into the first equation to get \[3(y+2) + y = 6\]

Answer 3

this simplifies into \[3y + 6 +y = 6\] which you can simplify further into \[4y+6 = 6\]

Answer 4

solving that equation, you get y=0
and then you plug that y into the second equation x= y+2 = 0+2 so x=2

Answer 5

your solution is the point (2,0)

Answer 6

Solve by elimination, x+8y=3 and 4x-2y=7

Answer 7

ok well first you multiply the second equation by 4 all the way across
\[16x-8y=28\]

Answer 8

then you add the two equations together and get \[(16x+x) + (8y-8y) = (3+28)\]

Answer 9

17x = 31 ==> x = 31/7

Answer 10

then plug in and solve for y

Answer 11

and next

Answer 12

hello

Answer 13

plus in the x value to the firs tequation
(31/17) + 8y = 3 = 51/17

Answer 14

8y = 20/17
y = (20/17)*(1/8) = 5/34