Question

HC]A laboratory experiment requires 2.0 L of a 1.5 M solution of hydrochloric acid (HCl), but the only available HCl is a 12.0 M stock solution. How could you prepare the solution needed for the lab experiment? Show all the work used to find your answer

Answer 1

\[M _{1}V _{1}=M _{2}V _{2}\]
You can set the "1" variables to be your diluted solution, and the "2" variables to be your stock solution. Then, solve for V2.

(1.5 M)(2.0 L) = (12.0 M)(V2)
V2 = 0.25 L of 12.0 M HCl