Question

The lengths of the sides of a right triangle are a and b, and the hypotenuse is c. Find the area of the triangle.

b = 2 in.; c = 6 in.

A = sq. in.

Answer 1

a would be the base b would be the height

Answer 2

thats correct

Answer 3

you can solve for a by doing \[\large \sqrt{6^2 - 2^2}\]

Answer 4

area = 1/2(bh), in your case area = 1/2(ab)
b = 2
a = 36 - 4 = 32. \[\sqrt{32} = 4\sqrt{2}. A = 4\sqrt{2}\]
area = 1/2(2)(4sqrt{2})
area = 4sqrt{2}

Answer 5

\[a = \sqrt{36 - 4} = \sqrt{32} = 4\sqrt 2\]

Answer 6

use formula of area \[\large A = \frac{4 \sqrt 2 \times 2}{2}\]

Answer 7

I also have this problem. The lengths of the sides of a right triangle are a and b, and the hypotenuse is c. Find the area of the triangle.
b = 2 in.; c = 6 in.
A = sq. in.

Answer 8

i just answered the question

Answer 9

what i wrote is easy enough to simplify... \[\Large \frac{4\sqrt 2 \times 2}{2}\]

Answer 10

sorry it didn't type right ....The lengths of the sides of a right triangle are a and b, and the hypotenuse is c. Find the area of the triangle.

A = 2/3 ft.; c = 4 ft.

A = sq. ft.