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Chemistry 14 Online
OpenStudy (anonymous):

15.0g of an unknown substance is heated from 25.0°C to 34.0°C. If 60.6 J of energy is absorbed, identify the unknown substance using the specific heat.

OpenStudy (anonymous):

\[q = mc \Delta T\] (60.6 J) = (15.0 g)(c)(34.0C - 25.0C) c = 0.45 J/gC This looks like Fe(s) (solid iron) to me.

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