if xy =4 then dy/dx = ? and please explain it
Apply product rule with respect to x:
how do I solve this then? I am new to calculus
differentiate you'll get xy'+y=0
\[\text{Use the product rule, }\frac{d}{dx}(u v)=v \frac{du}{dx}+u \frac{dv}{dx}\text{, where }u=x\text{ and }v=y\]
Basically for product rule I think of like this, xy =4 (copy left)(differentiate right) + (copy right)(differentiate left) where "left" is "x" and right is "y" so when you differentiate, (x)(dy/dx)+(y)(1)=0
This is implicit differentiation, did you learn the basics of differentiation first?
no, I started today. I was doing limit before it. Can you suggest me good tutorials on differntiation and derivative ..
its very helpful what you explained here but I need to clear the basic concepts of derivative first to solve this equation.
here's one http://www.youtube.com/watch?v=uPCjqfT0Ixg&list=PL58C7BA6C14FD8F48&index=20&feature=plpp_video
thank you very much ..
have you tried khanacademy?
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