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Mathematics 14 Online
OpenStudy (anonymous):

How to simplify (2n-1)!/(2n+1)!

OpenStudy (anonymous):

Factorials!

OpenStudy (anonymous):

Yes!

OpenStudy (anonymous):

do you understand how they work?

OpenStudy (anonymous):

Yeah I do N! = (n-1) * n

OpenStudy (anonymous):

Alright so the bottom can be simplified more

OpenStudy (anonymous):

using the propertiesof factorials

OpenStudy (anonymous):

Which properties? I'm not fimiliar

OpenStudy (anonymous):

familiar *

OpenStudy (anonymous):

\[\frac{(2n-1)!}{(2n-1)!(2n)(2n+1)}\]

OpenStudy (anonymous):

How did you get the bottom like that?

OpenStudy (anonymous):

so you know how factorials work since you have 2n-1, start with n = 1, 2 ,3 , 4, .......(2n-1)

OpenStudy (anonymous):

1,3,5,7......(2n+1)

OpenStudy (anonymous):

(2n-1 i mean

OpenStudy (anonymous):

Ahhhh still not seeing it idk why

OpenStudy (anonymous):

alright so lets start from (n+2)

OpenStudy (anonymous):

(n+2)!=(n+2)(n+1)!

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

(n+k)!=(n+k)(n+k-1)!

OpenStudy (anonymous):

is basically the property

OpenStudy (anonymous):

Now can you do the work to show how you got to that denominator?

OpenStudy (anonymous):

using the property i showed above (2n+1)!=(2n+1)(2n)! (2n)!=(2n)(2n-1)!

OpenStudy (anonymous):

so (2n+1)!=(2n+1)(2n)(2n-1)!

OpenStudy (anonymous):

it's basically your same property n!=(n)(n-1)! only only n in this specific case = 2n+1

OpenStudy (anonymous):

OHHHHHHHHHH , I had it the whole time. Just overlooked it

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

Thanks so much man! I got this now

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