Mathematics
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OpenStudy (anonymous):
How to simplify (2n-1)!/(2n+1)!
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OpenStudy (anonymous):
Factorials!
OpenStudy (anonymous):
Yes!
OpenStudy (anonymous):
do you understand how they work?
OpenStudy (anonymous):
Yeah I do N! = (n-1) * n
OpenStudy (anonymous):
Alright so the bottom can be simplified more
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OpenStudy (anonymous):
using the propertiesof factorials
OpenStudy (anonymous):
Which properties? I'm not fimiliar
OpenStudy (anonymous):
familiar *
OpenStudy (anonymous):
\[\frac{(2n-1)!}{(2n-1)!(2n)(2n+1)}\]
OpenStudy (anonymous):
How did you get the bottom like that?
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OpenStudy (anonymous):
so you know how factorials work since you have 2n-1, start with n = 1, 2 ,3 , 4, .......(2n-1)
OpenStudy (anonymous):
1,3,5,7......(2n+1)
OpenStudy (anonymous):
(2n-1 i mean
OpenStudy (anonymous):
Ahhhh still not seeing it idk why
OpenStudy (anonymous):
alright so lets start from (n+2)
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OpenStudy (anonymous):
(n+2)!=(n+2)(n+1)!
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
(n+k)!=(n+k)(n+k-1)!
OpenStudy (anonymous):
is basically the property
OpenStudy (anonymous):
Now can you do the work to show how you got to that denominator?
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OpenStudy (anonymous):
using the property i showed above
(2n+1)!=(2n+1)(2n)!
(2n)!=(2n)(2n-1)!
OpenStudy (anonymous):
so
(2n+1)!=(2n+1)(2n)(2n-1)!
OpenStudy (anonymous):
it's basically your same property
n!=(n)(n-1)! only
only n in this specific case = 2n+1
OpenStudy (anonymous):
OHHHHHHHHHH , I had it the whole time. Just overlooked it
OpenStudy (anonymous):
lol
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OpenStudy (anonymous):
Thanks so much man! I got this now