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OpenStudy (anonymous):
do i divide the 7 away first
OpenStudy (anonymous):
What are you looking for here
OpenStudy (anonymous):
is the eqn like this?
\[7^{7n+1} = 2401\]
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
ok then you need to deal with the 7n+1 first do you know about logs?
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OpenStudy (anonymous):
then convert RHS into exponential form and compare the powers of LHS and RHS
OpenStudy (anonymous):
i dnt remember hw to do tht
OpenStudy (anonymous):
no need of logs dear, 2401 is 7^ 4. just compare the powers
OpenStudy (anonymous):
n=3/7
OpenStudy (anonymous):
ah soz I missed that
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OpenStudy (anonymous):
O so i find the square root type thing
OpenStudy (anonymous):
common factor
OpenStudy (anonymous):
ok, if you didn't see the power thing then this always works
\[7^{7n+1} = 2401\]\[\ln(7)\times7n+1 = \ln(2401)\]\[7n+1 = \ln(2401)/\ln(7)\]\[7n = (\ln(2410/\ln(7))-1\]\[n = ((\ln(2410/\ln(7))-1)/7\]\[n=3/7\]
OpenStudy (anonymous):
now comparing powers is easier ill show you that as well
OpenStudy (anonymous):
\[7^{7n+1} =7^4\] so \[7n+1 = 4\]\[7n =3\] and \[n=3/7\] sorry I missed that first time but if you do then you need the other option.
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