Question

i feel so ashamed of asking this question lol but after several tries i give up ^^

[e^(x)*sqrt(e^(x))-e^(x)]/sqrt(e^(x))=e^(x)-sqrt(e^(x))

how??

Answer 1

u just need to multiple both side with squr(e^X)

Answer 2

note that squr (x)squr(x) =x and the same for any term

Answer 3

\[ \frac{e^{x}*\sqrt{e^{x}}-e^{x}}{\sqrt{e^x}}=e^x-\sqrt{e^x}\]

\[\sqrt{e^x}\sqrt{e^x} = e^x\]

Answer 4

[e^(x)*sqrt(e^(x))-e^(x)]/sqrt(e^(x))=e^(x)-sqrt(e^(x)) * sqrt (e^x)
e^(x)*sqrt(e^(x))-e^(x)]={e^(x)-sqrt(e^(x)} * sqrt (e^x)

Answer 5

@0x58 are you comfortable with these explanation?

Answer 6

yes but still can't get right right? cold you guys do it precisely??

Answer 7

e^x * sqrt(e^x)-e^x = e^x ( sqrt e^x - 1)

Answer 8

e^x ( sqrt e^x - 1) / sqrt e^x
= sqrt e^x ( sqrt e^x -1)
= 1 - sqrt e^x

Answer 9

You seem get stuck at factor sqrt ( e^x), so I go the easier way!

Answer 10

@0x58 Hope it's clear now!

Answer 11

\[\sqrt{e ^{x}}\left( e ^{x}\sqrt{e ^{x}}-e ^{x} \right) \div \sqrt{e ^{x}} \sqrt{e ^{x}}=e ^{x}\sqrt{e ^{x}} \sqrt{e ^{x}}-e ^{x} \sqrt{e ^{x}} \div e ^{x}=e ^{x}\times e ^{x} - e ^{x} \sqrt{e ^{x}} \div e ^{x}\]
is this right? if yes then what's next?

Answer 12

I can't read like that!
That's why I always separate them out:

e^x ( sqrt e^x - 1) / sqrt e^x
= sqrt e^x ( sqrt e^x -1)
= 1 - sqrt e^x

Answer 13

Oops
= e^x - sqrt e^x ( typo at the last line)

Answer 14

It's already extra difficult to read your post!

Answer 15

what about this??

{sqrt(e ^(x))*[e^(x)*sqrt(e^(x))-e^(x)]} / sqrt(e ^(x))*sqrt(e ^(x))
={e^(x)*sqrt(e^(x))*sqrt(e^(x))-e^(x)*sqrt(e^(x))} / e^(x)
={e^(x)*e^(x) - e^(x) * sqrt(e^(x))} / e^(x)

Answer 16

@0x58
is it a new question ?

Answer 17

no! just wanted to make sure that it's correct