An ideal gas is in equilibrium at initial state with temperature T=137oC, pressure P = 0.75Pa and volume V = 0.75 m3. If there is a change in state in which the gas undergoes an isothermal process to a final state of equilibrium during which the volume is doubled. Calculate the temperature and pressure of the gas at this final state

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anonymous · Answer

very easy

anonymous · Answer

Isothermal == Temperature remains same

anonymous · Answer

p1V1 = p2V2 using Ideal Gas law

anonymous · Answer

volume is doubled, that means pressure will become half

anonymous · Answer

that clear?

anonymous · Answer

Ditto to telltoamit.  PV=NkT if NkT is the same then P has to half its value if V is doubled.

anonymous · Answer

theprof can u answer my ques
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