11. A catapult launches a boulder with an upward velocity of 148 ft/s. The height of the boulder, h, in feet after t seconds is given by the function . How long does it take the boulder to reach its maximum height? What is the boulder’s maximum height? Round to the nearest hundredth, if necessary. (1 point)

9.25 s; 30 ft
4.63 s; 640.5 ft
4.63 s; 1056.75 ft
4.63 s; 372.25 ft

Question

11.   A catapult launches a boulder with an upward velocity of 148 ft/s. The height of the boulder, h, in feet after t seconds is given by the function . How long does it take the boulder to reach its maximum height? What is the boulder’s maximum height? Round to the nearest hundredth, if necessary.  (1 point)

9.25 s; 30 ft
4.63 s; 640.5 ft
4.63 s; 1056.75 ft
4.63 s; 372.25 ft

cwrw238 · Answer

at maxim height velocity = 0
use the formula
v = u + at
v=0,u=148, a = -32
0 = 148 - 32t
32t = 148
t = 148/32 = 4.625 seconds

cwrw238 · Answer

thats 4.63 to nearest hundredth
maximum height
can be found by using the formula

s = (u + v)t /2
   = (148 + 0)*4.63/ 2
    =  342.62 ft

cwrw238 · Answer

which is not one of your options
but i'm pretty sure i'm correct